Precalculus (6th Edition) Blitzer

Published by Pearson

Chapter 7 - Review Exercises - Page 877: 34

Answer

$(-2,-3)$, $(2,-3)$, $(-3,2)$, $(3,2)$

Work Step by Step

Re-arrange the given two equations and then use the substitution method to get $x^2+(x^2-7)^2=13$ or, $x^4-13x^2+36=0$ This gives: $(x+2)(x-2)(x+3)(x-3)=0$ when $x=-2$ then we have $y=(-2)^2 -7=-3$ when $x=2$ then we have $y=(2)^2 -7=-3$ when $x=-3$ then we have $y=(-3)^2 -7=2$ when $x=3$ then we have $y=(3)^2 -7=2$ Hence, our answers are: $(-2,-3)$, $(2,-3)$, $(-3,2)$, $(3,2)$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.