Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Review Exercises - Page 877: 27


$(1,-1)$, $(-1,1)$

Work Step by Step

Re-arrange the given two equations and then use the substitution method to get $(-y)^2+y^2=2$ or, $2y^2=2$ or, $y=-1,1$ when $y=-1$ then we have $x=1$ when $y=1$ then we have $x=-1$ Hence, our answers are: $(1,-1)$, $(-1,1)$
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