Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Review Exercises - Page 877: 26


$(0,1)$, $(-3,4)$

Work Step by Step

Re-arrange the given two equations and then use the substitution method to get $x+(x^2+2x+1)=1$ or, $x^2+3x=0$ or, $x(x+3)=0$ when $x=0$ then we have $y=(0)^2+2(0)+1=1$ when $x=-3$ then we have $y=(-3)^2+2(-3)+1=4$ Hence, our answers are: $(0,1)$, $(-3,4)$
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