Precalculus (6th Edition) Blitzer

The solution on the interval $[0,2\pi )$, correct to four decimal places, is $0.8319$ or $2.3097$.
We have to calculate the equation using a calculator in radian mode: $\theta =\text{si}{{\text{n}}^{-1}}0.7392\approx 0.8319.$ Therefore, the sine is positive in quadrants I and II, $x\approx 0.8319\$ or $x\approx \pi -0.8319$ And the value of $\pi$ is 3.14159. Hence, the value of $x$ is: \begin{align} & x\approx 3.14159-0.8319 \\ & \approx 2.3097. \end{align}