Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.5 - Trigonometric Equations - Exercise Set - Page 704: 102

Answer

The given equation has no solutions.

Work Step by Step

We have to solve the equation as follows: $\cos x-5=3\cos x+6$ Arrange the given equation in such a way that the cosine functions are on one side and the real numbers are on the other as follows: $\begin{align} & \cos x-3\cos x=6+5 \\ & -2\cos x=11 \\ & \cos x=\frac{-11}{2} \end{align}$ Thus, the cosine value of all the numbers always lies in the interval $\left[ -1,1 \right]$; the cosine value cannot be less than 1. So, $\cos x=\frac{-11}{2}$ is not possible.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.