## Precalculus (6th Edition) Blitzer

$0.4636, 0.9828, 3.6052, 4.1244$; graph (b).
Step 1. Factoring the equation, we have $(2tan(x)-1)(2tan(x)-3)=0$, thus $tan(x)=\frac{1}{2}=0.5$ and $tan(x)=\frac{3}{2}=1.5$ Step 2. For $tan(x)=0.5$, we have solutions in $[0,2\pi)$ as $x_0=tan^{-1}0.5\approx0.4636$ and $x=\pi+x_0\approx3.6052$ Step 3. For $tan(x)=1.5$, we have solutions in $[0,2\pi)$ as $x_0=tan^{-1}1.5\approx0.9828$ and $x=\pi+x_0\approx4.1244$ Step 4. Based on the above zeros, we can identify the corresponding graph as (b).