Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.5 - Trigonometric Equations - Exercise Set - Page 704: 61

Answer

$\{0,\pi \}$

Work Step by Step

Step 1. Factor the equation as $tan^2(x)(cos(x)-1)=0$, which gives two solutions $tan(x)=0$ and $cos(x)=1$ Step 2. For $tan(x)=0$, we can find all x-values in $[0,2\pi)$ as $x=0,\pi$ Step 3. For $cos(x)=1$, we can find all x-values in $[0,2\pi)$ as $x=0$ Step 4. The solutions for the original equation in $[0,2\pi)$ are $\{0,\pi \}$
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