Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.4 - Trigonometric Functions of Any Angle - Exercise Set - Page 575: 9



Work Step by Step

Here, $ x= -1$; $ r=1$ The trigonometric ratios are as follows: $\cos \theta =\dfrac{x}{r}$ Then, we have $\cos (\pi) =\dfrac{-1}{1}=-1$
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