Answer
$-1$
Work Step by Step
Here, $ x= -1$; $ y=0$ and $ r=\sqrt {(1)^2+(0)^2}=1$
The trigonometric ratios are as follows:
$\sec \theta =\dfrac{r}{x}$
Then, we have $\sec (\pi) =\dfrac{1}{-1}=-1$
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