Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.4 - Trigonometric Functions of Any Angle - Exercise Set: 43

Answer

$\dfrac{\pi}{6}$

Work Step by Step

RECALL: The following are the means on how to find the reference angle of an angle $\theta$ based on its position: (1) Quadrant I: $\theta$ (itself) (2) Quadrant II: $\pi-\theta$ (3) Quadrant III: $\theta - \pi$ (4) Quadrant IV: $2\pi-\theta$ $\frac{5\pi}{6}$ is in Quadrant II. Thus, using formula (2) above gives: reference angle of $\frac{5\pi}{6}$ is $\pi - \dfrac{5\pi}{6}=\dfrac{6\pi}{6}-\dfrac{5\pi}{6} = \dfrac{\pi}{6}$
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