# Chapter 4 - Section 4.4 - Trigonometric Functions of Any Angle - Exercise Set - Page 575: 10

$0$

#### Work Step by Step

Here, $x= -1$; $y=0$ and $r=\sqrt {(1)^2+(0)^2}=1$ The trigonometric ratios are as follows: $\tan \theta =\dfrac{y}{x}$ Then, we have $\tan (\pi) =\dfrac{0}{-1}=0$

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