## Precalculus (6th Edition) Blitzer

a. Let $y=e$; we have $\frac{ln(x)}{ln(e)}=ln(x)-lne$ or $ln(x) =ln(x)-1$ b. Graph the left side and right side functions as shown in the figure. We can see that the two curves are different, indicating that $ln(x)\ne ln(x)-1$ . Thus the original statement is not true.