Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 476: 101

Answer

True.

Work Step by Step

Apply the change of base property: $\displaystyle \quad \log_{b}M=\frac{\log_{a}M}{\log_{a}b}$ (on the LHS, change base from 3 to 7) $\displaystyle \log_{3}7=\frac{\log 7}{\log 3}$ Apply the basic property $\log_{b}b=1$ $=\displaystyle \frac{1}{\log_{7}3}$=RHS Thus, the statement is true.
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