## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 476: 104

#### Answer

a. $t=\frac{1}{c}[ln\frac{A}{A-N}]$ b. about $20.5$ weeks.

#### Work Step by Step

a. We can rewrite the formula as $t=\frac{1}{c}[ln\frac{A}{A-N}]$ b. Given $A=65, N=30, c=0.03$, we have $t=\frac{1}{0.03}[ln\frac{65}{65-30}]\approx20.5$ weeks.

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