Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 476: 103


a. $10log\frac{I}{I_0}$ b. $20\ db$

Work Step by Step

a. We can rewrite the formula as $D=10(logI-logI_0)=10log\frac{I}{I_0}$ b. Given $\frac{I_1}{I_2}=100$ where $1$ is for the louder sound and $2$ for the softer sound, we have $D_1-D_2=10log\frac{I_1}{I_0}-10log\frac{I_2}{I_0}=10log\frac{I_1}{I_2}=10log100=20\ db$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.