## Precalculus (6th Edition) Blitzer

We know that whenever a function $f\left( x \right)$ of degree $n$ is divided by another function $g\left( x \right)$ of degree $m$, the degree of the quotient must be $n-m$. Well, in the above case, the degree of $f\left( x \right)$ is $6$ when divided by $g\left( x \right)$ of degree $3$; the degree of the quotient must be $6-3=3$. But, the given degree of the quotient is $2$. Hence, the given statement is false.