Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 365: 62

Answer

$11$, see explanations.

Work Step by Step

Step 1. Based on the Remainder Theorem, $f(-6)$ is the remainder when performing a division of $f(x)$ by $x+6$. Step 2. Perform a synthetic division as shown in the figure; we can get the remainder as $f(-6)=11$. Step 3. It can be seen that we can obtain $f(-6)$ easily using the Remainder Theorem and with division instead of evaluating $f(-6)$ directly.
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