Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 365: 54

Answer

$8x^2-12x+4$

Work Step by Step

Step 1. Let the length be $y$ units; we have the area as $(x+\frac{3}{4})y=8x^3-6x^2-5x+3$, which gives $y=\frac{8x^3-6x^2-5x+3}{x+\frac{3}{4}}$ Step 2. Using synthetic division as shown in the figure, we have $y=8x^2-12x+4$$
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