## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 10 - Test - Page 1126: 9

#### Answer

$a_{n}=4 +5(n-1)$ and $a_{12}=59$

#### Work Step by Step

We need to use the formula $a_n =a_1+(n-1) d$ ....(1) Here, $a_1=4$ and $d=5$ $a_{n}=4 +5(n-1)$ Now, plug in: $n=12$ $a_{12}=4 +(12-1) \times (5)$ and $a_{12}=4 +55 =59$ So, $a_{n}=4 +5(n-1)$ and $a_{12}=59$

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