Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Test - Page 1126: 2



Work Step by Step

In order to set up the summation notation, we must calculate that value which keeps constantly changing. That value will be designated as the $i$ term. The remaining terms would remain constant in the summation notation. Thus, we get the summation notation as: $\sum_{i=1}^{5} (i^2+10)=\sum_{i=1}^{5} (i^2)+\sum_{i=1}^{5} (10)=\sum_{i=1}^{5} (i^2)+10 \times \sum_{i=1}^{5} 1$ Now, $=(1)^2+(2)^2+(3)^2+(4)^2+(5)^2+10(1+1+1+1+1)$ $=105$
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