Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Test - Page 1126: 3



Work Step by Step

In order to set up the summation notation, we must calculate that value which keeps constantly changing. That value will be designated as the $i$ term. The remaining terms would remain constant in the summation notation. Thus, we get the summation notation as: $\sum_{i=1}^{20} (3i-4)=3 \sum_{i=1}^{20} i+(-4) \sum_{i=1}^{10} 1$ $=3 \sum_{i=1}^{20} i-4(20)$ $=3 \times \dfrac{20 \cdot 21}{2}+80$ $=550$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.