Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Test - Page 1126: 4


$\dfrac{65,534}{3}$ or, $21,844.\overline{6}$

Work Step by Step

$ S_{15}=\dfrac{-2[ 1-(-2)^{15}]}{1-(-2)}$ $= \dfrac{-2( 2^{15-1})}{1+2}$ $=\dfrac{-2( 32768-1)}{3}$ $=\dfrac{65,534}{3}$ $=21,844.\overline{6}$
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