## Precalculus (6th Edition) Blitzer

$a_{1}=1;a_2=\dfrac{-1}{4};a_3=\dfrac{1}{9};a_4=\dfrac{-1}{16};a_5=\dfrac{1}{25}$
In order to find the five terms, we will plug in $n=1$ to $5$ in the given equation. Since we have a recursive formula, use the first term to get the second term. By plugging in higher values of $n$, we will get larger order terms. So, the first $5$ terms of the sequence are: $a_{1}=1;a_2=\dfrac{-1}{4};a_3=\dfrac{1}{9};a_4=\dfrac{-1}{16};a_5=\dfrac{1}{25}$