Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Exercise Set - Page 1073: 8

Answer

$-2,12,-72,432,-2592$

Work Step by Step

Here $ a_{n}=-6a_{n-1}$ We are given that $ a_1=-2$ $ a_2=-6a_{2-1} = (-6)(-2)=12 ;\\ a_3=-6a_{3-1} = (-6)(12)=-72 ; \\ a_4= -6a_{4-1} = (-6)(-72)=432; \\ a_5=-6a_{5-1} = (-6)(432)=-2592$ Hence, the first five terms are: $-2,12,-72,432,-2592$
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