#### Answer

$10, -30,90,-270,810$

#### Work Step by Step

Here $ a_{n}=-3a_{n-1}$
We are given that $ a_1=10$
$ a_2=-3a_{2-1} = (-3)(10)=-30 ;\\ a_3=-3a_{3-1} = (-3)(-30)=90 ; \\ a_4= -3a_{4-1} = (-3)(90)=-270; \\ a_5=-3a_{5-1} = (-3)(-270)=810$
Hence, the first five terms are: $10, -30,90,-270,810$