## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Exercise Set - Page 1073: 6

#### Answer

$10, -30,90,-270,810$

#### Work Step by Step

Here $a_{n}=-3a_{n-1}$ We are given that $a_1=10$ $a_2=-3a_{2-1} = (-3)(10)=-30 ;\\ a_3=-3a_{3-1} = (-3)(-30)=90 ; \\ a_4= -3a_{4-1} = (-3)(90)=-270; \\ a_5=-3a_{5-1} = (-3)(-270)=810$ Hence, the first five terms are: $10, -30,90,-270,810$

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