## Precalculus (6th Edition) Blitzer

$-8192$
The general formula to find the nth term of a Geometric sequence is given as: $a_{n}=a_1r^{n-1}$ We are given that $a_1=4, r=-2; n=12$ Now, $a_{12}=4 \times (-2)^{12-1}=4 (-2)^{11}$ $\implies a_{12}=-8192$