Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Exercise Set - Page 1073: 14



Work Step by Step

The general formula to find the nth term of a Geometric sequence is given as: $ a_{n}=a_1r^{n-1}$ We are given that $ a_1=8000, r=-\dfrac{1}{2}; n=30$ Now, $ a_{30}=8000 \times (-\dfrac{1}{2})^{30-1}=8000 (-\dfrac{1}{2})^{29}$ $\implies a_{30}=-\dfrac{1}{67108.864}$
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