## Precalculus (6th Edition) Blitzer

$-6, 30, -150,750,-3750$
Here $a_{n}=-5a_{n-1}$ We are given that $a_1=-6$ $a_2=-5a_{2-1} = (-5)(-6)=30 ;\\ a_3=-5a_{3-1} = (-5)(30)=-150 ; \\ a_4= -5a_{4-1} = (-5)(-150)=750; \\ a_5=-5a_{5-1} = (-5)(750)=-3750$ Hence, the first five terms are: $-6, 30, -150,750,-3750$