Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1125: 75

Answer

The value of the provided expression $_{13}{{C}_{11}}$ is $78$

Work Step by Step

We plug the values into the combination formula: $\begin{align} & _{13}{{C}_{11}}=\frac{13!}{11!\left( 13-11 \right)!} \\ & =\frac{13!}{11!2!} \\ & =\frac{13\times 12\times 11!}{2\times 11!} \\ & =78 \end{align}$
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