## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 10 - Review Exercises - Page 1125: 48

#### Answer

$\dfrac{-18}{5}=-3.6$

#### Work Step by Step

The sum of an infinite geometric sequence is given as: $S=\dfrac{a_1}{1-r}$ Here, $a_1=-6$ and common ratio is: $r=\dfrac{-2}{3}$ $S=\dfrac{a_1}{1-r}$ Now, $S=\dfrac{-6}{1-(-\dfrac{2}{3})}=\dfrac{-18}{3+2}=-3.6$

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