Answer
$\dfrac{-18}{5}=-3.6$
Work Step by Step
The sum of an infinite geometric sequence is given as: $ S=\dfrac{a_1}{1-r}$
Here, $ a_1=-6$ and common ratio is: $ r=\dfrac{-2}{3}$
$ S=\dfrac{a_1}{1-r}$
Now,
$ S=\dfrac{-6}{1-(-\dfrac{2}{3})}=\dfrac{-18}{3+2}=-3.6$
