## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 10 - Review Exercises - Page 1125: 74

#### Answer

The value of the provided expression is $_{8}{{C}_{3}}$ = $56$

#### Work Step by Step

We compare the provided expression with the standard form and get $n=8,r=3$. Put the values into the combination formula: That is, \begin{align} & _{8}{{C}_{3}}=\frac{8!}{3!\left( 8-3 \right)!} \\ & =\frac{8!}{3!5!} \\ & =\frac{8\times 7\times 6\times 5!}{3\times 2\times 5!} \\ & =56 \end{align}

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