Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1125: 74


The value of the provided expression is $_{8}{{C}_{3}}$ = $56$

Work Step by Step

We compare the provided expression with the standard form and get $ n=8,r=3$. Put the values into the combination formula: That is, $\begin{align} & _{8}{{C}_{3}}=\frac{8!}{3!\left( 8-3 \right)!} \\ & =\frac{8!}{3!5!} \\ & =\frac{8\times 7\times 6\times 5!}{3\times 2\times 5!} \\ & =56 \end{align}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.