Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1125: 46

Answer

$\frac{27}{2}=13.5$

Work Step by Step

The sum of a infinite geometric sequence is given as: $ S=\dfrac{a_1}{1-r}$ Here, $ a_1=9$ and Common Ratio: $ r=\dfrac{1}{3}$ $ S=\dfrac{a_1}{1-r}$ Now, $ S=\dfrac{9}{1-\dfrac{1}{3}}=\dfrac{27}{3-1}=\frac{27}{2}=13.5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.