Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1125: 63

Answer

The value of the given binomial coefficient is 4005.

Work Step by Step

Let us consider the provided expression, $\begin{align} & \left( \begin{matrix} 90 \\ 2 \\ \end{matrix} \right)=\frac{90!}{2!\left( 90-2 \right)!} \\ & =\frac{90!}{88!2!} \\ & =\frac{90\cdot 89}{2\cdot 1} \\ & =4005 \end{align}$
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