## Precalculus (6th Edition) Blitzer

$f(x)$, domain $[0, \infty)$, range $[-1,\infty)$ $f^{-1}$, domain $[-1,\infty)$, range $[0,,\infty)$
Step 1. Find the inverse of the first function as $g(x)=f^{-1}=\sqrt {x+1}$ Step 2. For function $f(x)=x^2-1, x\geq0$, shown as the red curve in the figure, we can identify its domain as $[0, \infty)$ and its range as $[-1,\infty)$ Step 3. For function $g(x)=f^{-1}=\sqrt {x+1}$, shown as the blue curve in the figure, we can identify its domain as $[-1,\infty)$ and its range as $[0,\infty)$