Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Test - Page 305: 15

Answer

$f(x) $, domain $[0, \infty)$, range $[-1,\infty)$ $f^{-1} $, domain $[-1,\infty)$, range $[0,,\infty)$
1581415616

Work Step by Step

Step 1. Find the inverse of the first function as $g(x)=f^{-1}=\sqrt {x+1}$ Step 2. For function $f(x)=x^2-1, x\geq0$, shown as the red curve in the figure, we can identify its domain as $[0, \infty)$ and its range as $[-1,\infty)$ Step 3. For function $g(x)=f^{-1}=\sqrt {x+1}$, shown as the blue curve in the figure, we can identify its domain as $[-1,\infty)$ and its range as $[0,\infty)$
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