Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Test - Page 306: 16

Answer

The value of $f\left( x-1 \right)$ with the functions $f\left( x \right)={{x}^{2}}-x-4$ and $g\left( x \right)=2x-6$ is ${{x}^{2}}-3x-2$

Work Step by Step

To calculate the value of $f\left( x-1 \right)$, substitute $x-1$ in place of $x$. $x\to x-1$ Now, substitute $x-1$ in place of $x$ in the function $f\left( x \right)$ and get $\begin{align} & f\left( x-1 \right)={{\left( x-1 \right)}^{2}}-\left( x-1 \right)-4 \\ & ={{x}^{2}}-2x+1-x+1-4 \\ & ={{x}^{2}}-3x-2 \end{align}$ Therefore, $f\left( x-1 \right)={{x}^{2}}-3x-2$. Hence, the value of $f\left( x-1 \right)$ with the functions $f\left( x \right)={{x}^{2}}-x-4$ and $g\left( x \right)=2x-6$ is ${{x}^{2}}-3x-2.$
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