## Precalculus (6th Edition) Blitzer

The values are $g\left( -1 \right)=4$ and $g\left( 7 \right)=2$.
The function $g\left( x \right)$ is defined as $\sqrt{x-3}$ , for each value of $x\ge 3$. The function $g\left( x \right)$ is defined as $3-x$ , for each value of $x<3$. So, for $x=-1$ , substitute the value of x in $3-x$ as follows: \begin{align} & g\left( -1 \right)=3-\left( -1 \right) \\ & =3+1 \\ & =4 \end{align} Now, for $x=7$ , substitute the value of x in $\sqrt{x-3}$ as follows: \begin{align} & g\left( 7 \right)=\sqrt{7-3} \\ & =\sqrt{4} \\ & =2 \end{align} Thus, the values are $g\left( -1 \right)=4$ and $g\left( 7 \right)=2$.