Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Test - Page 305: 7

Answer

See the graph below:

Work Step by Step

In order to draw the graph of the function $f\left( x \right)=-\frac{1}{3}x+2$, replace $f\left( x \right)$ with y. $y=-\frac{1}{3}x+2$. So, put $x=0$ in the equation and get $\begin{align} & y=-\frac{1}{3}\left( 0 \right)+2 \\ & y=2 \end{align}$ Again, put $x=3$ in the equation and get $\begin{align} & y=-\frac{1}{3}\left( 3 \right)+2 \\ & y=-1+2 \\ & y=1 \end{align}$ Thus, two solutions of the equation are $\left( 0,2 \right)\text{ and}\left( 3,1 \right)$.
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