Answer
See the graph below:
Work Step by Step
We know that a circle has center $\left( h,k \right)$ and radius $r$. The general equation of the circle is ${{\left( x-h \right)}^{2}}+{{\left( y-k \right)}^{2}}={{r}^{2}}$.
The equation ${{\left( x+2 \right)}^{2}}+{{\left( y-1 \right)}^{2}}=9$ can be rewritten as ${{\left( x-\left( -2 \right) \right)}^{2}}+{{\left( y-1 \right)}^{2}}={{3}^{2}}$.
Therefore, the center of the circle is $\left( h,k \right)=\left( -2,1 \right)$ and radius $r=3$.
