Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 557: 9

Answer

$C \approx23.2^\circ$; $B \approx56.8^\circ$; $b \approx4.25$

Work Step by Step

Step 1. Use the Law of Sines: $\frac{2}{sinC}=\frac{5}{sin100^\circ}$, thus $C=sin^{-1}(\frac{2sin100^\circ}{5})\approx23.2^\circ$ Step 2. $B=180-A-C\approx56.8^\circ$; Step 3. $\frac{b}{sin56.8^\circ}=\frac{5}{sin100^\circ}$, thus $b=\frac{5sin56.8^\circ}{sin100^\circ}\approx4.25$
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