Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 557: 22

Answer

$18.79$ square units

Work Step by Step

By definition, $K=\dfrac{bc\cdot \sin(A)}{2}.$ Hence, here we have $K=\dfrac{4\cdot10\cdot \sin(70^\circ)}{2}\approx18.79.$
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