Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 557: 8

Answer

$C =100^\circ$; $b \approx0.65$, $c \approx1.29$

Work Step by Step

Step 1. $C=180-A-B=100^\circ$; Step 2. Use the Law of Sines: $\frac{b}{sin30^\circ}=\frac{c}{sin100^\circ}=\frac{1}{sin50^\circ}$, thus $b=\frac{sin30^\circ}{sin50^\circ}\approx0.65$, $c=\frac{sin100^\circ}{sin50^\circ}\approx1.29$
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