Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 557: 23

Answer

$6$ square units

Work Step by Step

By Heron's formula, $K=\sqrt{s(s-a)(s-b)(s-c)}$, where $s=\frac{a+b+c}{2}.$ Hence, here we have: $s=\frac{4+3+5}{2}=6$ Thus, $K=\sqrt{6(6-4)(6-3)(6-5)}=6.$
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