Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 557: 2

Answer

$sin\theta=\frac{\sqrt 3}{2}$, $cos\theta=\frac{1}{2}$, $tan\theta=\sqrt 3$, $cot\theta=\frac{\sqrt 3}{3}$, $sec\theta=2$, $csc\theta=\frac{2\sqrt 3}{3}$.

Work Step by Step

Letting $x=2, r=4, y=\sqrt {4^2-2^2}=2\sqrt 3$, we have: $sin\theta=\frac{\sqrt 3}{2}$, $cos\theta=\frac{1}{2}$, $tan\theta=\sqrt 3$, $cot\theta=\frac{\sqrt 3}{3}$, $sec\theta=2$, $csc\theta=\frac{2\sqrt 3}{3}$.
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