Answer
$-\frac{4}{3}$
Work Step by Step
Step 1. Letting $cos^{-1}(-\frac{3}{4})=t, \frac{\pi}{2}\lt t\lt \pi$, we have $cos(t)=-\frac{3}{4}$
Step 2. Thus $sec(cos^{-1}(-\frac{3}{4}))=sec(t)=\frac{1}{cos(t)}=-\frac{4}{3}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Chapter Test - Page 507: 6
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