Answer
$\frac{7}{3}$
Work Step by Step
If $\tan{y}=x$, then $\tan^{-1}{x}=y.$
We know that $f(f^{-1}(x))=x$, hence $\tan{(\tan^{-1}){(\frac{7}{3})}}=\frac{7}{3}.$ We also need that $-\infty \leq x\leq \infty$, which is true here.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Chapter Test - Page 507: 4
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