Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Chapter Test - Page 507: 14

Answer

See below.

Work Step by Step

Using trigonometric identities, we have: $LHS=\frac{sin(\alpha+\beta)}{tan\alpha+tan\beta}=\frac{sin\alpha cos\beta + cos\alpha sin\beta}{sin\alpha/cos\alpha+sin\beta/cos\beta}=\frac{sin\alpha cos\beta + cos\alpha sin\beta}{\frac{sin\alpha cos\beta + cos\alpha sin\beta}{cos\alpha cos\beta}}=cos\alpha cos\beta=RHS$
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