Answer
$-\frac{\pi}{4}$
Work Step by Step
Letting $sin^{-1}(-\frac{\sqrt 2}{2})=t, -\frac{\pi}{2}\lt t \lt 0$, we have $sin(t)=-\frac{\sqrt 2}{2}$
Therefore:
$t=-\frac{\pi}{4}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Chapter Test - Page 507: 2
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