Answer
0.20
Work Step by Step
I know that $\cot{x}=\frac{1}{\tan{x}}$, hence $\cot^{-1}{x}=\tan^{-1}{\frac{1}{{x}}}$.
I use a calculator in RAD mode and then round the result, hence: $\cot^{-1}{(5)}=0.1974\approx0.20.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Chapter Test - Page 507: 10
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