Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Chapter Test - Page 507: 11

Answer

See below.

Work Step by Step

The identity is equivalent to $(csc\theta+cot\theta)(csc\theta-cot\theta)=(sec\theta+tan\theta)(sec\theta-tan\theta)\longrightarrow csc^2\theta-cot^2\theta=sec^2\theta-tan^2\theta \longrightarrow 1=1$ Which is true.
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