Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 497: 40

Answer

$-\frac{\sqrt {6}}{4}$

Work Step by Step

Step 1. Using the given figures, we have $a=-\sqrt {5-4}=-1, b=-\sqrt {1-\frac{1}{16}}=-\frac{\sqrt {15}}{4}$ Step 2. $g(\frac{\alpha}{2})=cos(\frac{\alpha}{2})=-\sqrt {\frac{1+cos\alpha}{2}}=-\sqrt {\frac{1+(-1/4)}{2}}=-\frac{\sqrt {6}}{4}$
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